5+21c+4c^2=

Solution for 5+21c+4c^2= equation:

Simplifying
5 + 21c + 4c2 = 0

Solving
5 + 21c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + c)(1 + 4c) = 0

Subproblem 1
Set the factor '(5 + c)' equal to zero and attempt to solve:

Simplifying
5 + c = 0

Solving
5 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + c = 0 + -5
c = 0 + -5

Combine like terms: 0 + -5 = -5
c = -5

Simplifying
c = -5
Subproblem 2
Set the factor '(1 + 4c)' equal to zero and attempt to solve:

Simplifying
1 + 4c = 0

Solving
1 + 4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 4c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4c = 0 + -1
4c = 0 + -1

Combine like terms: 0 + -1 = -1
4c = -1

Divide each side by '4'.
c = -0.25

Simplifying
c = -0.25
Solution
c = {-5, -0.25}